Formula / Procedure to figure support size or dimensions
I have built a cross to be used in Lenten Easter services in our church. I’d like to build a stand whereas the cross is in fixture standing upright. I had planned on building a square tube mounted on a flat piece of wood such as plywood to support the cross in an upright position. I’m sure that the weight of the cross, plus height and width are all part of the equation to support the cross. I don’t want to overbuild the support but I’m not sure as to the height of the square supporting tube or the dimensions of the flat piece affixed to the square tube, that would be needed to support the cross. Can you please advise a formula or some other means of determining what sizes I’ll need to complete the project.
I appreciate any and all recommendations.
Thank You!
Frank
Replies
Frank,
I don't know of a formula that doesn't involve complex engineering calculations.
For example the width of the base would be much different if the 'center of gravity' of the cross were high rather then low. And obviously on a cross the c-g is high. Do as suggested - build the cross, then experiment until you find a width-of-base that is stable.
Jerry
Jerry:
Thank you for your input. I have just returned from chruch and found a working example of a base. It looks a bit overbuilt but I think I'll go out to the garage and and start with something a bit smaller and see how it goes. Winging it I guess until I get something which will support without being overbuilt, yet sufficient to hold the cross uprigth without fear of it falling over.
Thanks and Happy Easter!
Frank
Steve:
I've just found an example at church that I was unaware of. It looks to be a little overbuilt but it works. I may try to scale the base down using scrap and wing it from there. I just didn't want ot build something that looked like it would withstand a major earth quake.
Thanks and Happy Easter
Frank
Frank,
What are the dimensions of the cross, are you talking about something a foot high for the altar or a piece that might be 8 feet tall?
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